AIEEE 2004 Math Solved Paper

Section: Mathematics

Question : 33 of 68

Marks: +1, -0

A function y=f(x) has a second order derivative f′′(x)=6(x−1). If its graph passes through the point (2,1) and at that point the tangent to the graph is y=3x−5, then the function is

[AIEEE 2004]

(x+1)2
(x−1)3
(x+1)3
(x−1)2

Validate

Go to Question:

Prev Question

Next Question