The sum of the first n terms of the series 1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+. . . is \frac{n(n+1)^2}{2} when {\n} is even. When {\n} is odd the sum is [AIEEE 2004]

AIEEE 2004 Math Solved Paper

Section: Mathematics

Question : 17 of 68

Marks: +1, -0

The sum of the first n terms of the series 12+2.22+32+2.42+52+2.62+... is ‌

n(n+1)2

when n is even. When n is odd the sum is

[AIEEE 2004]

Go to Question:

Prev Question

Next Question