AIEEE 2003 Math Solved Paper

Section: Mathematics

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Question : 63 of 66

Marks: +1, -0

lim

x→‌

π

2

‌

[1−tan(

x

2

)][1−sin‌x]

[1+tan(‌

x

2

)][π−2x]3

is

[AIEEE 2003]

∞
‌
1
8
0
‌
1
32

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