AIEEE 2002 Physics Solved Paper

Moment of Inertia of a circular wire about an axis nn′ passing through the centre of the circle and perpendicular to the plane of the circle =MR2 As shown in the figure, X-axis and Y-axis lies in the plane of the ring. Then by perpendicular axis theorem
IX+IY=IZ
⇒2IX=MR2[. as IX−IY (by symmetry) and .IZ=MR2]
∴IX=‌

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MR2