The differential rate law for the reaction {\H}_2+ {\I}_2 \to 2 {\HI} is [AIEEE 2002]

Correct Answer is : −2d[H2]dt=−2d[I2]dt=d[HI]dt

-\frac{d[H_2]}{d t}=-\frac{d[I_2]}{d t}=-\frac{d[H I]}{d t}

\frac{d[H_2]}{d t}=\frac{d[I_2]}{d t}=\frac{d[H I]}{d t}

\frac{1}{2} \frac{d[H_2]}{d t}=\frac{1}{2} \frac{d[I_2]}{d t}=-\frac{d[H I]}{d t}

-2 \frac{d[H_2]}{d t}=-2 \frac{d[I_2]}{d t}=\frac{d[H I]}{d t}

AIEEE 2002 Chemistry Solved Paper

Section: Chemistry

Question : 45 of 76

Marks: +1, -0

The differential rate law for the reaction H2+I2→2‌HI is

[AIEEE 2002]

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