The angle between two vectors A^{\to} and B^{\to} given by-

Correct Answer is : cosθ=→A⋅→B|→A||→B|

\cos \theta = \overrightarrow{{A} \cdot \overrightarrow{B}}/\overrightarrow{2|{A}||\overrightarrow{B}|}

\tan \theta = \overrightarrow{{A} \cdot \overrightarrow{B}}/\overrightarrow{|{A}||\overrightarrow{B}|}

\sin \theta = \overrightarrow{{A} \cdot \overrightarrow{B}}/\overrightarrow{|{A}||\overrightarrow{B}|}

\cos \theta = \overrightarrow{{A} \cdot \overrightarrow{B}}/\overrightarrow{|{A}||\overrightarrow{B}|}

Agniveer Vayu or IAF Group X 6 Nov 2020 Paper

Question : 21 of 75

Marks: +1, -0

The angle between two vectors

→

and

→

given by-

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