AFCAT Model Paper 8

Let the number of coins of 50 p and 1 Re.be x each
Drawing coins of 50 paise = 1/3rd of the total 50 paise coins
Remaining coins of 50 paise in the box = 2/3rd of the total 50 paise coins
Drawing coins of 1 rupee = 1/4th of the total 1 rupee coins
Remaining coins of 1 rupee in the box = 3/4th of the total 1 rupee coins
Now, According to the question

2x

3

×

50

100

+

3x

4

×1=26
⇒

x

3

+

3x

4

=26
⇒ 4x + 9x = 26 × 12
⇒ 13x = 26 × 12
⇒ x = 24
∴ Required number of coins initially in the cash-box = 24 + 24 = 48