AFCAT Model Paper 5

Given:
Number of days for which food provided = 30 days
Number of people who left =

1

5

Calculation:
Let the food consumed by 1 man in 1 day be x and total men be y
Let the time after which people left be z days
Then the total quantity of food = 30xy
Food consumed by y men in z days = xyz
Remaining food = 30xy - xyz = xy(30 - z)
After z days, total men =

4y

5

Food consumed by

4y

5

men in 1 day =

4xy

5

Time taken for 4y/5 men to consume remaining food =

xy(30−z)

(4x y 5 )

=

5(30−z)

4

⇒

5(30–z)

4

=30
⇒ z = 6 days