AFCAT II 26 AUG 2022 Shift 1 Paper

5 men +4 women can complete the work in 10 days.
4 women +7 men can do the same work in 8 days.

(M1×D1×H1)

W1

=

(M2×D2×H2)

W2

Let the efficiency of man be M and efficiency of woman be W
(5M+4W)×10=(4M+7W)×8
⇒50M+40W=32M+56W
⇒18M=16W
⇒M=(

8

9

)W
Again, one day work of 5 men \& 4 women
5M+4W=1∕10
⇒5×(

8

9

)W+4W=

1

10

⇒W(

40

9

+4)=

1

10

⇒W(

76

9

)=1∕10
⇒W=

9

760

Hence, one day work of 11 women
⇒11×

9

760

=

99

760

∴11 women can complete the same work in ‌

760

99

days.