AFCAT II 26 AUG 2022 Shift 1 Paper

Probability of occurrence of the event:
P(E)=‌

n(E)

n(S)

Where,
n(E)= Number of favorable outcome
n(S)= Number of possible outcome
When the dice are rolled, the possible outcomes are
n(S)=62=36
Favourable outcomes
(2,6),(3,5),(3,6),(4,4), (4,5),(4,6),(5,3), (5,4),(5,5,),(5,6),(6,2),(6,3), (6,4),(6,5),(6,6)
⇒n(E)=15
Using the above formula, the required probability
P=‌

n(E)

n(S)

=‌

15

36

=‌

5

12

∴ Required probability is ‌

5

12

.