AFCAT II 24 Aug 2025 Shift 1 Paper

Let the initial amount of milk be 7 x litres and the initial amount of water be 5 x litres.
After replacing 9 litres of milk with water:
New amount of milk =7x−9 litres
New amount of water =5x+9 litres
New ratio of milk to water =(7x−9):(5x+9)
Given that the new ratio is 7:9, we can set up the equation:
‌

7x−9

5x+9

=‌

7

9

Calculations:
‌‌

7x−9

5x+9

=‌

7

9

‌⇒9(7x−9)=7(5x+9)
‌⇒63x−81=35x+63
‌⇒63x−35x=63+81
‌⇒28x=144
‌⇒x=‌

144

28

‌⇒x=5.14
Initial amount of milk =7x=7×5.14=36 litres