AFCAT II 24 Aug 2019 Paper

Home •_______________• Temple
Time taken by dog to reach the temple =

4

8

=

1

2

‌hour
Distance Covered by man in

1

2

‌hr=4×

1

2

=2‌km
Now, Let the dog meets man after t hour
then, 8×t+4×t=(4–2).
12t=2⇒t=

1

6

‌hour
Distance covered by the dog to reach the temple afterfirst meeting =8×

1

6

=

4

3

‌km
Similarly, distance covered by the dog to reach thetemple after second meeting =

4

3

×

1

3

=

4

9

‌km
after third meeting =

4

9

×

1

3

=

4

27

‌km ...... so on
total distance covered by the dog towards the temple =4+

4

3

+

4

9

+

4

27

+.....∞

4

1− 1 3

=

4

2 3

=

4×3

2

=6km