AFCAT II 23 Aug 2025 Shift 2 Paper

48−3[5+8{4−4(9−2)+6}−12]÷3
First, solve the innermost bracket (9-2):
⇒48−3[5+8{4−4×7+6}−12]÷3
Next, solve the multiplication inside the curly braces } :
⇒48−3[5+8{4−28+6}−12]÷3
Now, solve the addition and subtraction inside the curly braces \{ \} from left to right:
‌⇒48−3[5+8{−24+6}−12]÷3
‌⇒48−3[5+8{−18}−12]÷3
Then, solve the multiplication inside the square bracket [ ]:
‌⇒48−3[5+(−144)−12]÷3
‌⇒48−3[5−144−12]÷3
‌⇒48−3[−139−12]÷3
‌⇒48−3[−151]÷3
‌⇒48−(−453)÷3
‌⇒48−(−151)
‌⇒48+151
‌⇒199