AFCAT II 2016 Solved Paper

Let rate of upstream = x kmph and rate of downstream = y kmph
Then
‌‌

30

x

+‌‌

44

y

=10
‌and‌quad‌‌

40

x

+‌‌

55

y

=13 On solving we get x = 5, y = 11
So, rate of upstream = 5Km/hr and rate of downstream= 11Km/hr
Rate of current =‌‌

1

2

[11−5]=3‌km∕hr