AFCAT I 22 Jan 2025 Shift 1 Paper

Let the speed of the train be xkm∕hr.
Relative Speed of Train and First Man:
Relative speed =(x−6)km∕hr=(x−6)×5∕18m∕s
Distance covered in crossing =(x−6)×5∕18×11 meters
Relative Speed of Train and Second Man:
Relative speed =(x−5)km∕hr=(x−5)×5∕18m∕s
Distance covered in crossing =(x−5)×5∕18×10 meters
Since the distance covered by the train in both cases is the same:
(x−6)×11=(x−5)×10
Simplifying the equation:
‌11x−66=10x−50
‌11x−10x=66−50
‌x=16km∕hr