AFCAT I 2016 Solved Paper

2(A + B + C)'s 1 day's work
=(‌‌

1

30

+‌‌

1

24

+‌‌

1

20

)=‌‌

15

120

=‌‌

1

8

Therefore, (A + B + C)'s 1 day's work =‌‌

1

2×8

=‌‌

1

16

Work done by A, B, C in 10 days =

10

16

=

5

8

Remaining work = (1−

5

8

)=

3

8

A's 1 day's work = (

1

16

−

1

24

)=

1

48

Now,

1

48

work is done by A in 1 day
So,

3

8

work will be done by A in (48×

3

8

) = 18 days