What is wrong with the following calculation? \int _{−1}^{3}\frac{1}{x^{2}}dx\: = \:−\frac{4}{3}

Correct Answer is : The value of the integral does not exist, since f(x) = 1x2 has an infinite discontinuity at x = 0

f(x) = \frac{1}{x^{2}} is continuous function on [-1, 3]

Fundamental Theorem of Calculus applies to discontinuous functions.

The value of the integral does not exist, since f(x) = \frac{1}{x^{2}} has an infinite discontinuity at x = 0

AAI ATC Junior Executive 27 Jul 2022 Shift 2 Paper

Question : 84 of 120

Marks: +1, -0

What is wrong with the following calculation?

∫ _{−1}^{3}\;{1}/{x^{2}}dx\: = \:−\;{4}/{3}

f(x) = $\;{1}/{x^{2}}$ is continuous function on [-1, 3]
Fundamental Theorem of Calculus applies to discontinuous functions.
The value of the integral does not exist, since f(x) = $\;{1}/{x^{2}}$ has an infinite discontinuity at x = 0
f(x) = $\;{1}/{x^{2}}$ < 0

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