The inverse of the matrix A = \left(\begin{array}{ccc}1 & 1 & 3 \ 1 & 3 & −3 \ −2 & −4 & −4 \ )\end{array} is:

Correct Answer is : (311.5−1.25−0.25−0.75−0.25−0.25−0.25)

\left(\begin{array}{ccc}3 & 1 & 1.5 \ −1.50 & −0.25 & −0.75 \ −0.25 & −0.25 & −0.25 \ )\end{array}

\left(\begin{array}{ccc}3 & 1 & 1.5 \ −1.25 & −0.75 & −0.25 \ −0.25 & −0.25 & −0.25 \ )\end{array}

\left(\begin{array}{ccc}3 & 1 & 1.5 \ −1.25 & −0.25 & −0.75 \ −0.25 & −0.25 & −0.25 \ )\end{array}

\left(\begin{array}{ccc}3 & 1 & 1.5 \ −1.25 & −0.25 & −0.75 \ −0.25 & −0.75 & −0.25 \ )\end{array}

AAI ATC Junior Executive 27 Jul 2022 Shift 2 Paper

Question : 120 of 120

Marks: +1, -0

The inverse of the matrix A =

{(\table 1 , 1 , 3 ; 1 , 3 , −3 ; −2 , −4 , −4 ; )}

is:

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