A ball is projected from origin in x y plane, with velocity u making an angle θ 0 with the x -axis. The horizontal range of the ball is:

Correct Answer is : (u2g)sin⁡2θ0

(\frac{u^{2}}{g}) \sin ⁡\theta _{0}

(\frac{u^{2}}{2g}) \sin ⁡2\theta _{0}

(\frac{u^{2}}{2g}) \sin ⁡\theta _{0}

(\frac{u^{2}}{g}) \sin ⁡2\theta _{0}

AAI ATC Junior Executive 27 Dec 2023 Shift 1 Paper

Question : 92 of 120

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A ball is projected from origin in x y plane, with velocity u making an angle θ₀ with the x -axis. The horizontal range of the ball is:

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