Solution of p\sqrt{x} + q\sqrt{y} = \sqrt{z} is

Correct Answer is : x−y=f(x−z)

\sqrt{x} + \sqrt{y} = f (\sqrt{x}−\sqrt{z})

\sqrt{x}−\sqrt{y} = f (\sqrt{x}−\sqrt{z})

\sqrt{x}−\sqrt{y} = f (\sqrt{x} + \sqrt{z})

\sqrt{x} + \sqrt{y} = f (\sqrt{x} + \sqrt{z})

AAI ATC Junior Executive 26 Dec 2015 Shift 1 Paper

Question : 95 of 120

Marks: +1, -0

Solution of

p{√{x}} + q{√{y}} = {√{z}}

Go to Question:

Prev Question

Next Question