The general solution of 3 sin 2 x - 7 sin x + 2 = 0 is:

Correct Answer is : x=nπ+(−1)nsin−1⁡13.

x = \frac{n\pi }{2} + (−1)^{n} \sin ^{−1}⁡\frac{1}{3}.

x = n\pi + (−1)^{n} \sin ⁡\frac{1}{3}.

x = n\pi + (−1)^{n} \sin ^{−1}⁡\frac{1}{3}.

x = 2n\pi + (−1)^{n} \sin ⁡\frac{1}{3}.

AAI ATC Junior Executive 21 Feb 2023 Shift 1 Paper

Question : 112 of 120

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The general solution of 3 sin² x - 7 sin x + 2 = 0 is:

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