The general solution of \frac{a\text{ }dx}{(b−c)yz} = \frac{b\text{ }dy}{(c−a)zx} = \frac{c\text{ }dz}{(a−b)xy} will be _____, where c 1 and c 2 are arbitary constants.

Correct Answer is : ax2 + by2 + cz2 = c1, a2x2 + b2y2 + c2z2 = c2

ax 2 + by 2 - cz 2 = c 1 , a 2 x 2 - b 2 y 2 + c 2 z 2 = c 2

ax + by + cz = c 1 , ax 2 = by 2 - by 2 - cz 2 = c 2

ax 2 + by 2 + cz 2 = c 1 , a 2 x 2 + b 2 y 2 + c 2 z 2 = c 2

ax - by + cz = c 1 , ax 2 + by 2 - cz 2 = c 2

AAI ATC Junior Executive 2018 Shift 3 Paper

Question : 74 of 120

Marks: +1, -0

The general solution of

\;{a\;\text " "\;dx}/{(b−c)yz} = \;{b\;\text " "\;dy}/{(c−a)zx} = \;{c\;\text " "\;dz}/{(a−b)xy}

will be _____, where c₁ and c₂ are arbitary constants.

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