The value of \binom{(\frac{2}{5})^{2}−(\frac{3}{10})^{2}..}/{\frac{3}{10}} of \frac{5}{42} \times [6−(2\frac{3}{4}−\frac{11}{12})] is:

AAI ATC Junior Executive 2018 Shift 3 Paper

Question : 31 of 120

Marks: +1, -0

The value of

\;{({2}/{5})^{2}−({3}/{10})^{2}..}/{{3}/{10}}

\;{5}/{42} × [6−(2\;{3}/{4}−\;{11}/{12})]

is:

Go to Question:

Prev Question

Next Question