The value of \int _{0}^{2\pi }⁡\int _{0}^{\pi \/ 4}⁡\int _{0}^{1}⁡r^{2} \sin ⁡\theta dr\:d\theta \:d\phi will be:

Correct Answer is : 2π3(2−1)

{\sqrt{2}\pi }/{3} (\sqrt{2} + \sqrt{3})

\frac{2\pi }{3} (\sqrt{2}−\sqrt{3})

{\sqrt{2}\pi }/{3} (\sqrt{2}−1)

AAI ATC Junior Executive 2018 Shift 1 Paper

Question : 96 of 120

Marks: +1, -0

The value of

∫ _{0}^{2π }⁡∫ _{0}^{π \/ 4}⁡∫ _{0}^{1}⁡r^{2} sin \;⁡θ dr\:dθ \:dφ

will be:

Go to Question:

Prev Question

Next Question