AAI ATC Junior Executive 2018 Shift 1 Paper

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Question : 94 of 120

Marks: +1, -0

The solution of differential equation u_n+3- 4u_n+2+ u_n+1+ 6u_n = 0 will be:

un = C1(1)n +C2(2)n + C3(3)n, where C₁, C₂, C₃ are constants.
u_n = C₁(-1)ⁿ +C₂(-2)ⁿ + C₃(-3)ⁿ, where C₁, C₂, C₃ are constants.
u_n = C₁(1)ⁿ + C₂(-2)ⁿ + C₃(3)ⁿ, where C₁, C₂, C₃ are constants.
u_n = C₁ (-1)ⁿ + C₂(2)ⁿ + C₃(3)ⁿ, where C₁, C₂, C₃ are constants.

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