The electric field between the two plates of a parallel plate (area = 5.0 × 10 -2 m 2 ) capacitor is given by E = (2.0 × 10 5 – 4.0 × 10 4 t) V/m where t is in second. What is the magnitude of the displacement current between the plates? (ε 0 = 8.85 × 10 -12 F/m)

Correct Answer is : 1.77 × 10-8 A

AAI ATC Junior Executive 2016 Shift 2 Paper

Question : 68 of 120

Marks: +1, -0

The electric field between the two plates of a parallel plate (area = 5.0 × 10^-2m²) capacitor is given by E = (2.0 × 10⁵ – 4.0 × 10⁴t) V/m where t is in second. What is the magnitude of the displacement current between the plates? (ε₀ = 8.85 × 10^-12 F/m)

8.46 × 10^-9 A
1.77 × 10^-8 A
5.95 × 10^-7 A
4.54 × 10^-6 A

Validate

Go to Question:

Prev Question

Next Question