If y = (sin -1 x) 2 then:

Correct Answer is : (1 - x2)yn + 2 - (2n + 1)xyn + 1 - n2yn = 0

(1 - x 2 )y n + 2 - (2n + 1)xy n + 1 - n 2 y n = 0

(1 - x 2 )y n + 2 - (2n + 1)xy n + 1 + n 2 y n = 0

(1 - x 2 )y n + 2 + (2n + 1)xy n + 1 - n 2 y n = 0

(1 - x 2 )y n + 2 - (2n - 1)xy n + 1 - n 2 y n = 0

AAI ATC Junior Executive 2016 Shift 1 Paper

Question : 84 of 120

Marks: +1, -0

If y = (sin^-1x)² then:

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