The electric field between two plates of a parallel plate (area = 8.0 × 10 -2 m 2 ) capacitor is given by E = (6.8 × 10 6 – 8.4 × 10 5 t) V/m, where t is in seconds. What is the magnitude of the displacement current between the plates? (ε 0 = 8.85 × 10 -12 F/m)

Correct Answer is : 5.95 × 10-7 A

AAI ATC Junior Executive 2016 Shift 1 Paper

Question : 102 of 120

Marks: +1, -0

The electric field between two plates of a parallel plate (area = 8.0 × 10^-2 m²) capacitor is given by E = (6.8 × 10⁶ – 8.4 × 10⁵ t) V/m, where t is in seconds. What is the magnitude of the displacement current between the plates? (ε₀ = 8.85 × 10^-12 F/m)

8.46 × 10^-9 A
3.57 × 10^-6 A
5.95 × 10^-7 A
7.36 × 10^-8 A

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