8RB Group D 23-Sep-2018 Shift 1 Solved Paper

Question : 58 of 100

Marks: +1, -0

In a test, Chandran secured 16 out of 45 marks.
He will take another test and to pass he needs to secure an overall

48 \%

marks. If the second test was out of

80,

and he just passed, what was his percentage marks in the second test?

Solution:

Let y% secure in second test and x marks.

16+x=(45+80)×{48}/{100}

125 \×48=100(16+x)

x=44

marks.

y \%

80=44

{y \×80}/{100}=44 \⇒y=55 \%

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