8RB Group D 23-Sep-2018 Shift 1 Solved Paper

Question : 52 of 100

Marks: +1, -0

Consider a two-digit number. The difference between the number and the number we get when its digits are reversed is 27 . If the sum of the digits in the given number is

9,

find the

{HCF}

of the number and the number when its digits are reversed.

Validate

Solution:

Let a two digit number

=10 x+y

(10 x+y)-(10 y+x)=27

x-y=3

...(1)
Given,

x+y=9

...(2)
After solving (1) and (2) ,

x=6, y=3

So, numbers

10 x+y=10 \×6+3=63

10 y+x=10 \×3+6=36

{HCF}

(63,36)=9

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