ICSE Class X Math 2016 Solved Paper

In the given figure below, $A D$ is a diameter. $O$ is the centre of the circle. $A D$ is parallel to $B C$ and $∠ C B D=32^{∘}$ . Find:

Question : 11 of 57

Marks: +1, -0

∠ B E D

Solution:

△ {\ABD}

∠ {\ABD}=\;90^{∘}

\;(\;\text " angle in a semicircle) "\;

∠ {\ADB}=\;32^{∘}

∠ {\BAD}=\;180-(90+32)

=\;58^{∘} .

∠ {\BAD}=\;∠ {\BED}

(angle in the same segment)

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