ICSE Class X Math 2015 Solved Paper

Three vertices of a parallelogram $A B C D$ taken in order are $A(3,6), B(5,10)$ and $C(3$ , 2) find:

Question : 9 of 52

Marks: +1, -0

equation of side

A B

of the parallelogram

A B C D

Solution:

Equation of

{\AB}

y-y_1\;=\;{y_2-y_1}/{x_2-x_1} (x-x_1)

y-6\;=\;{10-6}/{5-3}(x-3)

y-6\;=\;{4}/{2}(x-3)

y-6\;=2 x-6

2 x-y\;=0

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