ICSE Class X Math 2015 Solved Paper

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Question : 5 of 52
 
Marks: +1, -0
If A=[3x01] and B=[9160−y], find x and y when A2=B.
Solution:
Given : A=[3x01] and B=[9160−y]
A2=B
[3x01][3x01] =[9160−y]
[3×3+x×03×x+x×10×3+1×00×x+1×1]=[9160−y]
[94x01]=[9160−y]
By equality of matrices,
4x=16 and 1=−y
x=4 and y=−1
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