ICSE Class X Math 2015 Solved Paper

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ABC is a right angled triangle with ABC= 90.D is any point on AB and DE is perpendicular to AC. Prove that :
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Question : 47 of 52
 
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ADEACB.
Solution:
To Prove : ADEACB
(i) In ADE and ACB
(1) A=A [common]
(2) AED=ABC
=90 (given)
ADEACB [AA axiom]
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