ICSE Class X Math 2014 Solved Paper

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In △ABC,∠ABC=∠DAC.AB=8cm,AC= 4cm,AD=5cm.
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Question : 25 of 52
 
Marks: +1, -0
Prove that â–³ACD is similar to â–³BCA .
Solution:
In â–³ACD and â–³BCA
∠C=∠C (common)
∠ABC=∠DAC (given)
∴△ACD∼∆BCA(AA postulates)
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