ICSE Class X Math 2014 Solved Paper

In the figure, $\∠D B C=58° . B D$ is a diameter of the circle. Calculate:

Question : 14 of 52

Marks: +1, -0

∠ B E C

Solution:

∠ {\BEC}+∠ {\BDC}=180^{∘}

(

∵

BECD is a cyclic quadrilateral)

∠ {\BEC}\;=180^{∘}-∠ {\BDC}

\;=180^{∘}-32^{∘}

∠ {\BEC}\;=148^{∘}

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