ICSE Class X Math 2013 Solved Paper

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Question : 32 of 46
 
Marks: +1, -0
Find x and y if [x3xy4y][21]=[512]
Solution:
Given : [x3xy4y][21]=[512]
[2x+3x2y+4y]=[512]
[5x6y]=[512]
∴5x=5
⇒x=1
and 6y=12
⇒y=2
Hence, x=1 and y=2
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