Calculate the total amount of heat energy required to melt 200 {\g} of ice at 0^{\circ} {\C} to water at 100^{\circ} {\C}. (Specific latent heat of ice =336 {\Jg}^{-1}, specific heat capacity of water =4.2 {\Jg}^{-1}{ }^{\circ} {\C}^{-1})

ICSE Class 10 Physics 2023 Solved Paper - Question 70

Question : 70 of 76

Marks: +1, -0

Calculate the total amount of heat energy required to melt

200 {\g}

of ice at

0^{∘} {\C}

to water at

100^{∘} {\C}

.
(Specific latent heat of ice

=336 {\Jg}^{-1}

, specific heat capacity of water

=4.2 {\Jg}^{-1}{ }^{∘} {\C}^{-1})

Solution:

Ice at

0^{∘} {\C} {───▸}↖{Q_1}

water at

0^{∘} {\C} {───▸}↖{Q_2}

\water[\;\text " at "\; 100^{∘} {\C}]

Given

m=200 {\g},\; {\L}_{\;\text "ice "\;}=336 {\Jg}^{-1}

{\C}_{\;\text "water "\;}\;=4.2 {\Jg}^{-1}{ }^{∘} {\C}^{-1}

{\Q}_1\;=m {\L}

\;=200 × 336

\;=67,200 {\J}

{\Q}_2\;=m c ∆ {\T}

\;=200 × 4.2 ×(100-0)

\;=84000 {\J}

\;\text " Total amount of heat "\;\;=Q_1+Q_2

\;=67200+84000

\;={1 , 5 1 , 2 0 0} {J}

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