ICSE Class 10 Physics 2022 Solved Paper

Question : 37 of 45

Marks: +1, -0

Complete and rewrite the following nuclear reaction by filling the blanks.

{ }_{. . . . .}^{235} {\U} →{ }_{90}^{....} {\Th}+{ }_2^4 {\He}

Solution:

Atomic no. of Uranium

=90+2=92

Mass no. of Thorium

=235-4=231

{ }_{92}^{235} {\U} →{ }_{90}^{231} {\Th}+{ }_2^4 {\He}

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