ICSE Class 10 Physics 2019 Solved Paper

The diagram above shows a circuit with the key $k$ open. Calculate :

Question : 62 of 74

Marks: +1, -0

the current drawn from the cell when the key

k

is closed.

Solution:

When key

{\K}

is closed

I=\;{E}/{R}=\;{3.3}/{3}=1.1 {\A}

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