A solid of mass 50 {\g} at 150^{\circ} {\C} is placed in 100 {\g} of water at 11^{\circ} {\C} , when the final temperature recorded is 20^{\circ} {\C} . Find the specific heat capacity of the solid. (Specific heat capacity of water =4.2 {\j} \/ {\g}^{\circ} {\C} )

ICSE Class 10 Physics 2017 Solved Paper - Question 8

Question : 8 of 65

Marks: +1, -0

A solid of mass

50 {\g}

150^{∘} {\C}

is placed in 100

{\g}

of water at

11^{∘} {\C}

, when the final temperature recorded is

20^{∘} {\C}

. Find the specific heat capacity of the solid.
(Specific heat capacity of water

=4.2 {\j} \/ {\g}^{∘} {\C}

)

Solution:

Given : Mass of solid

(m_1) =50 {\g}

Initial temperature of solid

=150^{∘} {\C}

Mass of water

(m_2) =100 {\g}

Intial temperature of mixture

=11^{∘} {\C}

Final temperature of mixture

=20^{∘} {\C}

Specific heat capacity of water

( {\c}_2) =4.2 {\J} \/ {\g}^{∘} {\C}

By the principle of calorimetry,
Heat lost by hot body = Heat gained by cold body.

⇒\;m_1 c_1 ∆ {\T}_1\;=m_2 c_2 ∆ {\T}_2

⇒ 50 × c_1 ×(150-20)\;=100 × 4.2(20-11)

⇒ 50 × c_1 × 130\;=100 × 4.2 × 9

⇒\;c_1\;=\;{100 × 4.2 × 9}/{50 × 30}

\;=\;0.58 {\Jg}^{-1{ }^{∘} {\C}^{-1}}

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