ICSE Class 10 Physics 2017 Solved Paper

A pulley system with $V R=4$ is used to lift a load of $175 {\kgf}$ through a vertical height of $15 {\m}$ . The effort required is $50 {\kgf}$ in the downward direction. $(g=10 {\N} {\kg}^{-1})$
Calculate:

Question : 30 of 65

Marks: +1, -0

M.A. of the pulley system.

Solution:

\;\text " M.A. "\;=\;{\;\text " Load "\;}/{\;\text " Effort "\;}=\;{175 {\kgf}}/{50 {\kgf}}=3.5

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