ICSE Class 10 Physics 2017 Solved Paper

Question : 18 of 65

Marks: +1, -0

An electric bulb of resistance

500 Ω

, draws a current of

0.4 {\A}

. Calculate the power of the bulb and the potential difference at its end.

Solution:

Given:

{\R}=500 Ω, {\I}=0.4 {\A}, {\P}=

{\V}=

?
We know,
Power,

{\P}\;= {\I}^2 {\R}

\;=(0.4)^2 × 500

\;=80 {\W}

Potential difference,

{\V}\;=R

\;=0.4 × 500

\;=200 {\Volt} .

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