ICSE Class 10 Physics 2016 Solved Paper

From the diagram given below, answer the questions that follow:

Question : 32 of 73

Marks: +1, -0

What effort has to be applied at

C

to just raise the load

L=20 {\kgf}

Solution:

Given :

{\L}=20 {\kgf}, {\E}=

?
In equilibrium,

{\L}=2 {\T}

and

{\Effort} {\E}= {\T}

∴

Effort needed,

{\E}=\;{ {\L}}/{2}=\;{20 {\kgf}}/{2}

=10 {\kgf}

Go to Question:

Prev Question

Next Question