ICSE Class 10 Physics 2016 Solved Paper

Question : 21 of 73

Marks: +1, -0

Calculate the quantity of heat produced in a

20 Ω

resistor carrying

2.5 {\A}

current in 5 minutes.

Solution:

Given

: {\I}=2.5 {\Amp}, {\R}=20 Ω, t=5 × 60=

300 second.

\;\text " Head Produced "\;={( \;\text " Potential Difference "\;) } ↙{\Volts}

×(\;\text " Current "\;)↙{ \Ampere }×(\;\text " time "\;) ↙{\Second }

=VIt

=\; {\I}^2 {\R} t \;\; (\;\text " Ohm's law, V=IR "\;)

=\;\;{25}/{10} × \;{25}/{10} × 20 × 300

=\;37500 {\J}

=\;37.5 {\kJ} .

Hence,

37.5 {\kJ}

heat is produced.

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