ICSE Class 10 Physics 2015 Solved Paper

A cell of Emf $2 {\V}$ and internal resistance $1.2 Ω$ is connected with an ammeter of resistance $0.8 Ω$ and two resistors of $4.5 Ω$ and $9 Ω$ as shown in the diagram below :

Question : 60 of 74

Marks: +1, -0

What is the potential difference across the terminals of the cell?

Solution:

\;\;\text " Terminal Voltage (V) "\;

= {\E}- {\I} r=2-0.4 × 1.2

\;=2-0.48

\;=1.52 \;\text " volt. "

Go to Question:

Prev Question

Next Question