Solve the following numerical problem: [3] Ethane burns in oxygen according to the chemical equation : 2 {\C}_2 {\H}_6+7 {\O}_2 \to 4 {\CO}_2+6 {\H}_2 {\O} If 80 {\ml} of ethane is burnt in 300 {\ml} of oxygen, find the composition of the resultant gaseous mixture when measured at room temperature.

ICSE Class 10 Chemistry 2023 Solved Paper - Question 47

Question : 47 of 88

Marks: +1, -0

Solve the following numerical problem: [3] Ethane burns in oxygen according to the chemical equation :

2 {\C}_2 {\H}_6+7 {\O}_2 → 4 {\CO}_2+6 {\H}_2 {\O}

80 {\ml}

of ethane is burnt in

300 {\ml}

of oxygen, find the composition of the resultant gaseous mixture when measured at room temperature.

Solution:

Given:

2 {\C}_2 {\H}_6+7 {\O}_2 → 4 {\CO}_2+6 {\H}_2 {\O}

∵ 2

moles of ethane reacts with 7 moles of oxygen to produce -6 moles of

{\H}_2 {\O}+4

moles of carbondioxide.

2 {\ml}

. of ethane reacts with

7 {\ml}

. of oxygen =

4 {\ml}

. of carbon dioxide

+ {\ml}

{\H}_2 {\O}

∴ 80 {\ml}

. of ethane reacts with

280 {\ml}

. of oxygen

=160 {\ml}

. of

{\CO}_2+240 {\ml}

. of

{\H}_2 {\O}

In this reaction ethane in the limiting reagent and

20 {\ml}

. of oxygen will be left, unreacted.
The composition of the resultant gaseous mixture when measured at room temperature will be:

20 {\ml}

. of oxygen gas :

160 {\ml}

. of

{\CO}_2

and

240 {\ml}

. of

{\H}_2 {\O}

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