ICSE Class 10 Chemistry 2018 Solved Paper

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Aluminum carbide reacts with water according to the following equation :
Al4C3+12H2O→4Al(OH)3+3CH4
[Relative molecular weight of Al4C3=144; Al(OH)3=78]
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Question : 57 of 80
 
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What volume of methane at s.t.p. is obtained from 12g of aluminum carbide?
Solution:
Al4C3+12H2O→4Al(OH3)+3CH4144gm4×78gm3×22.4

If 144gm of Al4C3 releases 3×22.4l of CH4 at STP
then 12gm of Al4C3 releases 3×22.4144×12
=5.6l
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