ICSE Class 10 Chemistry 2015 Solved Paper

Consider the following reaction and based on the reaction answer the questions that follow :

( {\NH}_4) _2 {\Cr}_2 {\O}_7 \ {─────▸}↖{\;\text " heat "\;} {\N}_2( {\g})+4 {\H}_2 {\O}( {\g})+ {\Cr}_2 {\O}_3

Calculate:

Question : 61 of 85

Marks: +1, -0

the quantity in moles of nitrogen formed.

Solution:

252 {\gm}

( {\NH}_4) _2 {\Cr}_2 {\O}_7

release 28

{\g} \;\text " of "\; {\N}_2

Then

63 {\g}

( {\NH}_4) _2 {\Cr}_2 {\O}_7

release

{\N}_2

=\;{28 × 63}/{252}=7 {\g} \;\text ". "\;

No. of moles of

{\N}_2=\;{7}/{28}=0.25

moles.

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