ICSE Class 10 Chemistry 2015 Solved Paper

Give balanced chemical equations for the following conversions :

Question : 43 of 85

Marks: +1, -0

Ethanoic acid to ethyl ethanoate.

Solution:

\; {\CH}_3 {\COOH}+ {\C}_2 {\H}_5 {\OH}

\;\ {─────▸}↙{ {\H}_2 {\SO}_4}↖{\;\text " Conc. "\;}{ \;{ {\CH}_3 {\COOC}_2 {\H}_5}}↙{ {\;\text " ethyl ethanoate "\;}}+ {\H}_2 {\O}

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